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Oracle Linux 8 Advanced System Administration certification highlights the candidate's proficiency in managing and troubleshooting the Oracle Linux 8 operating system. Oracle Linux 8 Advanced System Administration certification opens up new opportunities for professionals seeking career growth and advancement in the IT industry.

Oracle 1Z0-106 Exam is designed for advanced system administrators working with the Oracle Linux 8 operating system. Oracle Linux 8 Advanced System Administration certification validates the candidate's skills and knowledge required to manage and maintain an Oracle Linux 8 system in a highly available data center environment.

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Oracle Linux 8 Advanced System Administration Sample Questions (Q20-Q25):

NEW QUESTION # 20
Examine this command:
# nft add rule inet filter input tcp dport 80 drop
Which two statements are true upon execution?

A. The rule updates the configuration on disk.
B. The rule applies to the input table.
C. TCP packets outbound on port 80 are dropped.
D. TCP packets inbound on port 80 are dropped.
E. All traffic inbound on port 80 is dropped.
F. The rule is applied to both IPv4 and IPv6 packets.

Answer: D,F

Explanation:
* Option A (Correct):The rule is applied to both IPv4 and IPv6 packets. Theinettable is used for filtering both IPv4 and IPv6 traffic, and since the rule is added to theinettable, it affects both IP versions.
* Option E (Correct):The rule drops TCP packets inbound on port 80. The rule specifies theinputchain in thefiltertable, and it drops (drop) all TCP traffic (tcp) destined for port 80 (dport 80), which means any incoming TCP traffic on port 80 will be dropped.
* Option B (Incorrect):The command does not automatically update the configuration on disk; the rule is applied immediately in memory but does not persist across reboots unless explicitly saved.
* Option C (Incorrect):The rule specifies TCP packets only, not all traffic. Therefore, it does not drop traffic for protocols other than TCP.
* Option D (Incorrect):Although this statement is correct, it is less specific than Option A, which is more accurate because it mentions both IP versions.
* Option F (Incorrect):The rule applies to inbound traffic, not outbound, so it does not drop outbound traffic.
Oracle Linux Reference:Refer to:
* OracleLinux 8: Managing Firewall Rules with nftables

NEW QUESTION # 21
Examine /etc/anacrontab:
SHELL=/bin/sh
PATH=/sbin:/bin:/usr/sbin:/usr/bin
MAILTO=root
# the maximal random delay added to the base delay of the jobs
RANDOM_DELAY=45
# the jobs are started during the following hours only
START_HOURS_RANGE=3-22
# period in days delay in minutes job-identifier command
1 5 dailyjob nice run-parts /etc/cron.daily
7 25 weeklyjob nice run-parts /etc/cron.weekly
@monthly 45 monthlyjob nice run-parts /etc/cron.monthly
Which two statements are true about the jobs scheduled in this file?

A. Scripts run by the third job are delayed between 45 and 90 minutes.
B. Scripts run by the second job are delayed between 31 and 70 minutes.
C. Jobs defined in this anacrontab file are randomly delayed by up to 51 minutes.
D. Scripts run by the first job are delayed between 11 and 45 minutes.
E. Jobs defined in this anacrontab file can be executed between 15:00 and 22:00

Answer: A,E

Explanation:
Understanding the anacrontab Entries:
The /etc/anacrontab file contains the following variables and job definitions:
SHELL=/bin/sh
PATH=/sbin:/bin:/usr/sbin:/usr/bin
MAILTO=root
# the maximal random delay added to the base delay of the jobs
RANDOM_DELAY=45
# the jobs are started during the following hours only
START_HOURS_RANGE=3-22
# period in days delay in minutes job-identifier command
1 5 dailyjob nice run-parts /etc/cron.daily
7 25 weeklyjob nice run-parts /etc/cron.weekly
@monthly 45 monthlyjob nice run-parts /etc/cron.monthly
Variables Explained:
* RANDOM_DELAY=45
* Specifies that arandom delaybetween 0 and 45 minutes is added to the base delay of each job.
* START_HOURS_RANGE=3-22
* Jobs are allowed to start only between03:00 (3 AM)and22:00 (10 PM).
Job Delays Calculated:
* First Job (dailyjob):
* Base Delay:5 minutes
* Random Delay:0 to 45 minutes
* Total Delay:5 + (0 to 45) =5 to 50 minutes
* Second Job (weeklyjob):
* Base Delay:25 minutes
* Random Delay:0 to 45 minutes
* Total Delay:25 + (0 to 45) =25 to 70 minutes
* Third Job (monthlyjob):
* Base Delay:45 minutes
* Random Delay:0 to 45 minutes
* Total Delay:45 + (0 to 45) =45 to 90 minutes
Option B: Jobs defined in this anacrontab file can be executed between 15:00 and 22:00
* Explanation:
* The START_HOURS_RANGE=3-22 setting allows jobs to start between03:00 and 22:00.
* Therefore, it's true that jobscan be executed between 15:00 (3 PM) and 22:00 (10 PM).
* This statement is correct because the specified time range falls within the allowed start hours.
* Oracle Linux Reference:
* OracleLinux 8: Scheduling Tasks- Section on "Anacron Configuration Files":
"The START_HOURS_RANGE variable defines the time window during which Anacron jobs can run." Option C: Scripts run by the third job are delayed between 45 and 90 minutes.
* Explanation:
* The third job (monthlyjob) has abase delay of 45 minutes.
* With a RANDOM_DELAY of up to 45 minutes, thetotal delaybefore execution is between45 and 90 minutes.
* Therefore, this statement is accurate.
* Oracle Linux Reference:
* OracleLinux 8: Scheduling Tasks- Section on "Understanding Anacron Job Delays":
"Each job's delay is calculated by adding its defined delay to a random value between 0 and RANDOM_DELAY." Why Other Options Are Not Correct:
* Option A:Scripts run by the first job are delayed between 11 and 45 minutes.
* Explanation:
* The first job (dailyjob) has a total delay between5 and 50 minutes(5-minute base delay plus up to 45 minutes random delay).
* Therefore, the statement specifying11 to 45 minutesis incorrect.
* Option D:Jobs defined in this anacrontab file are randomly delayed by up to 51 minutes.
* Explanation:
* The maximum random delay is set by RANDOM_DELAY=45, so the random delay is up to45 minutes, not 51.
* Therefore, this statement is false.
* Option E:Scripts run by the second job are delayed between 31 and 70 minutes.
* Explanation:
* The second job (weeklyjob) has a total delay between25 and 70 minutes(25-minute base delay plus up to 45 minutes random delay).
* The statement specifies a delay between31 and 70 minutes, which is incorrect because the minimum delay is 25 minutes.
Conclusion:
Options B and C are correct based on the configuration specified in /etc/anacrontab. They accurately reflect the possible execution times and delays for the jobs defined.

NEW QUESTION # 22
Which mdadm command creates a RAID-1 device consisting of two block volumes and one spare device?

A. mdadm -create /dev/md0 -level=0 -raid-devices=2 /dev/xvdd1 /dev/xvdd2 -spare-devices=1 /dev
/xvdd3
B. mdadm -create /dev/md0 -level=1 -raid-devices=2 /dev/xvdd1 /dev/xvdd2
C. mdadm -create /dev/md0 -level=1 -raid-devices=2 /dev/xvdd1 /dev/xvdd2 -spare-devices=1 /dev
/xvdd3
D. mdadm -create /dev/md0 -level=5 -raid-devices=2 /dev/xvdd1 /dev/xvdd2 -spare-devices=1 /dev
/xvdd3

Answer: C

Explanation:
The correct command to create a RAID-1 device (mirroring) consisting of two block volumes with one spare device is optionC:mdadm -create /dev/md0 -level=1 -raid-devices=2 /dev/xvdd1 /dev/xvdd2 -spare- devices=1 /dev/xvdd3.
* RAID Level 1:RAID-1, also known as mirroring, involves creating an exact copy (or mirror) of a set of data on two or more disks. This ensures data redundancy; if one disk fails, the other can still provide the data.
* mdadm Command Structure:Themdadmcommand is used to manage and monitor RAID devices on Linux. To create a new RAID array, the--createoption is used, followed by several parameters:
* /dev/md0: The name of the RAID device to be created.
* --level=1: Specifies RAID level 1 (mirroring).
* --raid-devices=2: Indicates the number of active devices (two in this case) to be used in the RAID array.
* /dev/xvdd1 /dev/xvdd2: The two block devices that will form the RAID-1 array.
* --spare-devices=1 /dev/xvdd3: Specifies one spare device (/dev/xvdd3). A spare device is used to automatically replace a failed device in the RAID array.
* Option Analysis:
* A.Incorrect because it specifies RAID level 5 (--level=5), which requires at least three devices and does not match the requirement for RAID-1.
* B.Incorrect because it does not include the--spare-devices=1option, meaning there is no spare device included in this configuration.
* C.Correct as it specifies RAID-1 (--level=1), two active devices (--raid-devices=2), and one spare device (--spare-devices=1).
* D.Incorrect because it specifies RAID level 0 (--level=0), which is a striped set (no redundancy), not a mirrored set (RAID-1).
Oracle Linux Reference:For more detailed information aboutmdadmand RAID configurations in Oracle Linux
8, refer to the following Oracle Linux documentation:
* OracleLinux 8 Managing Storage Devices - RAID Configuration
* OracleLinux 8 mdadm Manual
These references provide comprehensive details on RAID levels,mdadmcommand syntax, and options for creating and managing RAID arrays in Oracle Linux.

NEW QUESTION # 23
Examine this command and output:
$ ftp host01.example.com
Connected to host01.example.com (192.168.40.131).
220 (vsFTPd 3.0.2)
Name (host01.example.com:oracle):
After entering a carriage return, this error message is displayed:
530 Permission denied
Login Failed
ftp>
Why is the oracle user denied access to the FTP server on host01.example.com?

A. The oracle user does not exist on host01.example.com.
B. The oracle user is listed in /etc/vsftpd/user_list and USERLIST_ENABLE is set to YES in /etc/vsftpd
/vsftpd.conf.
C. The oracle user is listed in /etc/vsftpd/user_list and USERLIST_ENABLE is set to NO in /etc/vsftpd
/vsftpd.conf.
D. LOCAL_ENABLE is set to NO in /etc/vsftpd/vsftpd.conf.
E. The oracle user is listed in /etc/vsftpd/ftpusers.

Answer: B

Explanation:
The530 Permission deniederror indicates that the user is not allowed to log in. In vsFTPd, if theUSERLIST_ENABLEoption is set toYESin/etc/vsftpd/vsftpd.conf, and theoracleuser is listed in/etc/vsftpd
/user_list, that user is explicitly denied access to the FTP server.

NEW QUESTION # 24
Examine the contents of the /etc/exports file on an NFS server:
/status *(rw,async)
/usr/shared/tools *(all-squash,anonuid=501,anongid=501,ro)
/projects/big *(ro) pteam(rw)
The NFS server exports /usr/shared/tools to NFS clients. Which statement is true?

A. All clients can mount /usr/shared/tools read-only and all-squash overrides explicit mapping of the UID and GID defined by anonuid and anongid.
B. All clients except those with a local 501 user can mount /usr/shared/tools read-only.
C. All clients can mount /usr/shared/tools read-only and NFS explicitly maps all requests to the UID and GID of the unprivileged local 501 user.
D. All clients can mount /usr/shared/tools read-only and NFS ignores the directives defined by the anonuid and anongid options.
E. All clients can mount /usr/shared/tools read-only and NFS explicitly maps all requests to the UID and GID of the privileged local 501 user.

Answer: C

NEW QUESTION # 25
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